Difference between revisions of "Portal:Mathematics/From the forum"
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(Created page with "== Square root of a number == The squre root of whole number is always less than the that square number ( ex; sqare root of 25 is 5, 36 is 6 etc) but in decimal it is reverse ...") |
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| − | == Square root of a number == | + | =='''Some interesting exchanges from the STF mailing forum.'''== |
| + | To join the forum, visit this group [http://groups.google.com/group/mathssciencestf?hl=en-US here]. | ||
| + | |||
| + | === Square root of a number === | ||
The squre root of whole number is always less than the that square number ( ex; sqare root of 25 is 5, 36 is 6 etc) but in decimal it is reverse (ex; sqare root 0.8 is o.89) what is the reason? | The squre root of whole number is always less than the that square number ( ex; sqare root of 25 is 5, 36 is 6 etc) but in decimal it is reverse (ex; sqare root 0.8 is o.89) what is the reason? | ||
Revision as of 05:44, 5 June 2013
Some interesting exchanges from the STF mailing forum.
To join the forum, visit this group here.
Square root of a number
The squre root of whole number is always less than the that square number ( ex; sqare root of 25 is 5, 36 is 6 etc) but in decimal it is reverse (ex; sqare root 0.8 is o.89) what is the reason?
Let us take ex : sq root of 0.16 is 0.4 but it is greater than 0.16 Square rooting 16/100 = 4/10. The value of denominator is larger than numerator.. when u square root it, (square root16) / (square root100) Thus making the denominator smaller at the same time..ex : numerator: square root16 = 4; denominator: square root100 = 10